No. 4 Musketeers Open Up A-10 Tourney Against No. 5 Richmond
May 22, 2011
CINCINNATI - The Xavier baseball team will begin its hunt for a second conference title as the No. 4 seed in the 2011 Atlantic 10 Baseball Championship. The Musketeers will face No. 5 Richmond in the opening game of the conference tournament.
First pitch for the Musketeers and Spiders postseason tilt will commence at Noon on Wednesday from scenic Campbell Field in Camden, N.J.
The winner of the opening game will move on to face top seed Charlotte at Noon on Thursday. The loser will be forced to play an elimination game later that night against the loser of the No. 3 Dayton and No. 6 La Salle game. The winner will advance to face No. 2 Rhode Island on Thursday afternoon
Xavier finished the season by defeating Fordham in a critical extra-innings affair Saturday night, giving them a 30-25 overall record and 14-10 conference record. The Musketeers knocked in five runs in the top of the 14th inning to defeat the Rams 8-4. Xavier returns to the conference tournament for the fifth consecutive year, after closing the season by winning six of its last eight conference games.
Richmond enters the tournament with 26-25-2 overall mark and 13-11 league record. The Spiders lost two games to Saint Joseph's over the weekend. Richmond benefited from the conference tie breaking procedures to claim the fifth seed, after finishing in three-way tie with La Salle and St. Bonaventure
Wednesday's game will be the fourth meeting between the Musketeers and Spiders this season. In April Richmond took two of three games at Hayden Field. Xavier salvaged a win in the series finale, 14-1.
Xavier last won the conference tournament in 2009 as the third seed. The Musketeers won their final four games, including two straight against Rhode Island, to capture the program's first title that season.